(3x+12)=(9x-48)

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Solution for (3x+12)=(9x-48) equation: 



(3x+12)=(9x-48)

We move all terms to the left:

(3x+12)-((9x-48))=0

We get rid of parentheses

3x-((9x-48))+12=0



We calculate terms in parentheses: -((9x-48)), so:

(9x-48)

We get rid of parentheses

9x-48

Back to the equation:

-(9x-48)



We get rid of parentheses

3x-9x+48+12=0

We add all the numbers together, and all the variables

-6x+60=0

We move all terms containing x to the left, all other terms to the right

-6x=-60

x=-60/-6

x=+10

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