2/5p-4/7p=2

Solution for 2/5p-4/7p=2 equation:

2/5p-4/7p=2

We move all terms to the left:

2/5p-4/7p-(2)=0


Domain of the equation: 5p!=0

p!=0/5

p!=0

p∈R



Domain of the equation: 7p!=0

p!=0/7

p!=0

p∈R


We calculate fractions


14p/35p^2+(-20p)/35p^2-2=0

We multiply all the terms by the denominator


14p+(-20p)-2*35p^2=0

Wy multiply elements

-70p^2+14p+(-20p)=0

We get rid of parentheses

-70p^2+14p-20p=0

We add all the numbers together, and all the variables

-70p^2-6p=0

a = -70; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·(-70)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*-70}=\frac{0}{-140}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*-70}=\frac{12}{-140}
=-3/35
$