(3x+12)+(3x-11)=(8x-9)

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Solution for (3x+12)+(3x-11)=(8x-9) equation: 



(3x+12)+(3x-11)=(8x-9)

We move all terms to the left:

(3x+12)+(3x-11)-((8x-9))=0

We get rid of parentheses

3x+3x-((8x-9))+12-11=0



We calculate terms in parentheses: -((8x-9)), so:

(8x-9)

We get rid of parentheses

8x-9

Back to the equation:

-(8x-9)



We add all the numbers together, and all the variables

6x-(8x-9)+1=0

We get rid of parentheses

6x-8x+9+1=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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