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5(4-3)5K=10+2(3K+1
We move all terms to the left:
5(4-3)5K-(10+2(3K+1)=0
We add all the numbers together, and all the variables
515K-(10+2(3K+1)=0
We calculate terms in parentheses: -(10+2(3K+1), so:We add all the numbers together, and all the variables
10+2(3K+1
determiningTheFunctionDomain 2(3K+1+10
Back to the equation:
-(2(3K+1+10)
515K-(2(3K+11)=0
We calculate terms in parentheses: -(2(3K+11), so:
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| 40=2x-9x+5 | | 3x=8( | | (10x+4)+(10x+4)+(10x+4)+(10x+4)+(10x+4)+(10x+4)+(10x+4)+(10x+4)+(10x+4)+(10x+4)=1440 | | 6-5y=-34 | | 35+14x=22+40x | | 7x-12=-3x+48 | | a/3+1=2 | | 3x-(-36)=30 | | 6x+4–11x=-5–2x | | 8y-5=-y+ | | 4k/1-6/3k-9=1/3 | | (7x+12)+(2x-7)+(15x+8)=387 | | (7x+12)+(2x-7)+(15x+8)=180 | | x=10-200 | | w/3-10=18 | | x=10x200 | | 2(x+1)=3(2+x) | | 5/6*10=1/106/5=n/n | | 2(n+9)=-6(2n-5+8 | | -(7x-3)=7x+15 | | x=10+200 | | -7=x/3+9 | | 22r^2+18r=0 | | -3=5(n+3 | | 30x+45=90x+35 | | 2=x/8-10 | | (8x+7)+(5x+18)+(14x-11)+(10x+13)=360 | | P(4)=7x-3 | | 3x+2=+3x+2 | | 50-15=2c+6 | | 3(4m-1)=1 | | [4(x+3)/2=-10x |