(3x+1)2=(x+3)3

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Solution for (3x+1)2=(x+3)3 equation: 



(3x+1)2=(x+3)3

We move all terms to the left:

(3x+1)2-((x+3)3)=0

We multiply parentheses

6x-((x+3)3)+2=0



We calculate terms in parentheses: -((x+3)3), so:

(x+3)3

We multiply parentheses

3x+9

Back to the equation:

-(3x+9)



We get rid of parentheses

6x-3x-9+2=0

We add all the numbers together, and all the variables

3x-7=0

We move all terms containing x to the left, all other terms to the right

3x=7

x=7/3

x=2+1/3

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