3(x+2)-x=(x+1)3

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Solution for 3(x+2)-x=(x+1)3 equation: 



3(x+2)-x=(x+1)3

We move all terms to the left:

3(x+2)-x-((x+1)3)=0

We add all the numbers together, and all the variables

-1x+3(x+2)-((x+1)3)=0

We multiply parentheses

-1x+3x-((x+1)3)+6=0



We calculate terms in parentheses: -((x+1)3), so:

(x+1)3

We multiply parentheses

3x+3

Back to the equation:

-(3x+3)



We add all the numbers together, and all the variables

2x-(3x+3)+6=0

We get rid of parentheses

2x-3x-3+6=0

We add all the numbers together, and all the variables

-1x+3=0

We move all terms containing x to the left, all other terms to the right

-x=-3

x=-3/-1

x=+3

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