(3x+1)/7=(6x-1)/5

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Solution for (3x+1)/7=(6x-1)/5 equation: 



(3x+1)/7=(6x-1)/5

We move all terms to the left:

(3x+1)/7-((6x-1)/5)=0

We calculate fractions


3x/()+(-((6x-1)*7)/()=0



We calculate terms in parentheses: +(-((6x-1)*7)/(), so:

-((6x-1)*7)/(

We multiply all the terms by the denominator


-((6x-1)*7)



We calculate terms in parentheses: -((6x-1)*7), so:

(6x-1)*7

We multiply parentheses

42x-7

Back to the equation:

-(42x-7)



We get rid of parentheses

-42x+7

Back to the equation:

+(-42x+7)



We get rid of parentheses

3x/()-42x+7=0

We multiply all the terms by the denominator


3x-42x*()+7*()=0

We add all the numbers together, and all the variables

3x-42x*()=0

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