3z-3(6-2z)=27

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Solution for 3z-3(6-2z)=27 equation: 



3z-3(6-2z)=27

We move all terms to the left:

3z-3(6-2z)-(27)=0

We add all the numbers together, and all the variables

3z-3(-2z+6)-27=0

We multiply parentheses

3z+6z-18-27=0

We add all the numbers together, and all the variables

9z-45=0

We move all terms containing z to the left, all other terms to the right

9z=45

z=45/9

z=5

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