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(3x+1)(4x-21)=180
We move all terms to the left:
(3x+1)(4x-21)-(180)=0
We multiply parentheses ..
(+12x^2-63x+4x-21)-180=0
We get rid of parentheses
12x^2-63x+4x-21-180=0
We add all the numbers together, and all the variables
12x^2-59x-201=0
a = 12; b = -59; c = -201;
Δ = b2-4ac
Δ = -592-4·12·(-201)
Δ = 13129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-\sqrt{13129}}{2*12}=\frac{59-\sqrt{13129}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+\sqrt{13129}}{2*12}=\frac{59+\sqrt{13129}}{24} $
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