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(3x+1)(3x+1)=2*2-x
We move all terms to the left:
(3x+1)(3x+1)-(2*2-x)=0
We add all the numbers together, and all the variables
(3x+1)(3x+1)-(-1x+4)=0
We get rid of parentheses
(3x+1)(3x+1)+1x-4=0
We multiply parentheses ..
(+9x^2+3x+3x+1)+1x-4=0
We add all the numbers together, and all the variables
(+9x^2+3x+3x+1)+x-4=0
We get rid of parentheses
9x^2+3x+3x+x+1-4=0
We add all the numbers together, and all the variables
9x^2+7x-3=0
a = 9; b = 7; c = -3;
Δ = b2-4ac
Δ = 72-4·9·(-3)
Δ = 157
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{157}}{2*9}=\frac{-7-\sqrt{157}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{157}}{2*9}=\frac{-7+\sqrt{157}}{18} $
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