(x+1)(x+1)-(x+4)(x+2)=-67x

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Solution for (x+1)(x+1)-(x+4)(x+2)=-67x equation:



(x+1)(x+1)-(x+4)(x+2)=-67x
We move all terms to the left:
(x+1)(x+1)-(x+4)(x+2)-(-67x)=0
We get rid of parentheses
(x+1)(x+1)-(x+4)(x+2)+67x=0
We multiply parentheses ..
(+x^2+x+x+1)-(x+4)(x+2)+67x=0
We add all the numbers together, and all the variables
(+x^2+x+x+1)+67x-(x+4)(x+2)=0
We get rid of parentheses
x^2+x+x+67x-(x+4)(x+2)+1=0
We multiply parentheses ..
x^2-(+x^2+2x+4x+8)+x+x+67x+1=0
We add all the numbers together, and all the variables
x^2-(+x^2+2x+4x+8)+69x+1=0
We get rid of parentheses
x^2-x^2-2x-4x+69x-8+1=0
We add all the numbers together, and all the variables
63x-7=0
We move all terms containing x to the left, all other terms to the right
63x=7
x=7/63
x=1/9

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