(3x*3=16x+12)+(-16-12)

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Solution for (3x*3=16x+12)+(-16-12) equation: 



(3x*3=16x+12)+(-16-12)

We move all terms to the left:

(3x*3-(16x+12)+(-16-12))=0

We add all the numbers together, and all the variables

(3x*3-(16x+12)+(-28))=0



We calculate terms in parentheses: +(3x*3-(16x+12)+(-28)), so:

3x*3-(16x+12)+(-28)

We add all the numbers together, and all the variables

3x*3-(16x+12)-28

Wy multiply elements

9x-(16x+12)-28

We get rid of parentheses

9x-16x-12-28

We add all the numbers together, and all the variables

-7x-40

Back to the equation:

+(-7x-40)



We get rid of parentheses

-7x-40=0

We move all terms containing x to the left, all other terms to the right

-7x=40

x=40/-7

x=-5+5/7

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