15-3(2-4x)-7x=11(x-2)+3x

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Solution for 15-3(2-4x)-7x=11(x-2)+3x equation: 



15-3(2-4x)-7x=11(x-2)+3x

We move all terms to the left:

15-3(2-4x)-7x-(11(x-2)+3x)=0

We add all the numbers together, and all the variables

-3(-4x+2)-7x-(11(x-2)+3x)+15=0

We add all the numbers together, and all the variables

-7x-3(-4x+2)-(11(x-2)+3x)+15=0

We multiply parentheses

-7x+12x-(11(x-2)+3x)-6+15=0



We calculate terms in parentheses: -(11(x-2)+3x), so:

11(x-2)+3x

We add all the numbers together, and all the variables

3x+11(x-2)

We multiply parentheses

3x+11x-22

We add all the numbers together, and all the variables

14x-22

Back to the equation:

-(14x-22)



We add all the numbers together, and all the variables

5x-(14x-22)+9=0

We get rid of parentheses

5x-14x+22+9=0

We add all the numbers together, and all the variables

-9x+31=0

We move all terms containing x to the left, all other terms to the right

-9x=-31

x=-31/-9

x=3+4/9

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