(3x)=(8x+5)=(2x+11)

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Solution for (3x)=(8x+5)=(2x+11) equation: 



(3x)=(8x+5)=(2x+11)

We move all terms to the left:

(3x)-((8x+5))=0



We calculate terms in parentheses: -((8x+5)), so:

(8x+5)

We get rid of parentheses

8x+5

Back to the equation:

-(8x+5)



We get rid of parentheses

3x-8x-5=0

We add all the numbers together, and all the variables

-5x-5=0

We move all terms containing x to the left, all other terms to the right

-5x=5

x=5/-5

x=-1

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