8(4e+1)=7(6e-4)

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Solution for 8(4e+1)=7(6e-4) equation: 



8(4e+1)=7(6e-4)

We move all terms to the left:

8(4e+1)-(7(6e-4))=0

We multiply parentheses

32e-(7(6e-4))+8=0



We calculate terms in parentheses: -(7(6e-4)), so:

7(6e-4)

We multiply parentheses

42e-28

Back to the equation:

-(42e-28)



We get rid of parentheses

32e-42e+28+8=0

We add all the numbers together, and all the variables

-10e+36=0

We move all terms containing e to the left, all other terms to the right

-10e=-36

e=-36/-10

e=3+3/5

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