(3x)/8=9/(2x)

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Solution for (3x)/8=9/(2x) equation:


D( x )

2*x = 0

2*x = 0

2*x = 0

2*x = 0 // : 2

x = 0

x in (-oo:0) U (0:+oo)

(3*x)/8 = 9/(2*x) // - 9/(2*x)

(3*x)/8-(9/(2*x)) = 0

(3*x)/8+(-9/2)*x^-1 = 0

3/8*x^1-9/2*x^-1 = 0

(3/8*x^2-9/2*x^0)/(x^1) = 0 // * x^2

x^1*(3/8*x^2-9/2*x^0) = 0

x^1

(3/8)*x^2-9/2 = 0

(3/8)*x^2-9/2 = 0

DELTA = 0^2-(4*(3/8)*(-9/2))

DELTA = 27/4

DELTA > 0

x = ((27/4)^(1/2)+0)/(2*(3/8)) or x = (0-(27/4)^(1/2))/(2*(3/8))

x = 4/3*(27/4)^(1/2) or x = 4/3*(27/4)^(1/2)

x in { 4/3*(27/4)^(1/2), 4/3*(27/4)^(1/2)}

x in { 4/3*(27/4)^(1/2), 4/3*(27/4)^(1/2) }

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