(5-i)=(2+3i)z

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Solution for (5-i)=(2+3i)z equation:


Simplifying
(5 + -1i) = (2 + 3i) * z

Remove parenthesis around (5 + -1i)
5 + -1i = (2 + 3i) * z

Reorder the terms for easier multiplication:
5 + -1i = z(2 + 3i)
5 + -1i = (2 * z + 3i * z)

Reorder the terms:
5 + -1i = (3iz + 2z)
5 + -1i = (3iz + 2z)

Solving
5 + -1i = 3iz + 2z

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-3iz' to each side of the equation.
5 + -1i + -3iz = 3iz + -3iz + 2z

Combine like terms: 3iz + -3iz = 0
5 + -1i + -3iz = 0 + 2z
5 + -1i + -3iz = 2z

Add '-5' to each side of the equation.
5 + -1i + -5 + -3iz = -5 + 2z

Reorder the terms:
5 + -5 + -1i + -3iz = -5 + 2z

Combine like terms: 5 + -5 = 0
0 + -1i + -3iz = -5 + 2z
-1i + -3iz = -5 + 2z

Reorder the terms:
5 + -1i + -3iz + -2z = -5 + 2z + 5 + -2z

Reorder the terms:
5 + -1i + -3iz + -2z = -5 + 5 + 2z + -2z

Combine like terms: -5 + 5 = 0
5 + -1i + -3iz + -2z = 0 + 2z + -2z
5 + -1i + -3iz + -2z = 2z + -2z

Combine like terms: 2z + -2z = 0
5 + -1i + -3iz + -2z = 0

The solution to this equation could not be determined.

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