(3x)/(2x+1)=5/2

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Solution for (3x)/(2x+1)=5/2 equation: 



(3x)/(2x+1)=5/2

We move all terms to the left:

(3x)/(2x+1)-(5/2)=0



Domain of the equation: (2x+1)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-1

x!=-1/2

x!=-1/2

x∈R



We add all the numbers together, and all the variables

3x/(2x+1)-(+5/2)=0

We get rid of parentheses

3x/(2x+1)-5/2=0

We calculate fractions


6x/(4x+2)+(-10x-5)/(4x+2)=0

We multiply all the terms by the denominator


6x+(-10x-5)=0

We get rid of parentheses

6x-10x-5=0

We add all the numbers together, and all the variables

-4x-5=0

We move all terms containing x to the left, all other terms to the right

-4x=5

x=5/-4

x=-1+1/4

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