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5y-(3y-2)+6=2(y+4
We move all terms to the left:
5y-(3y-2)+6-(2(y+4)=0
We get rid of parentheses
5y-3y-(2(y+4)+6+2=0
We add all the numbers together, and all the variables
2y-(2(y+4)+6+2=0
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