(3x)+(x+45)=(6x+5)

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Solution for (3x)+(x+45)=(6x+5) equation: 



(3x)+(x+45)=(6x+5)

We move all terms to the left:

(3x)+(x+45)-((6x+5))=0

We get rid of parentheses

3x+x-((6x+5))+45=0



We calculate terms in parentheses: -((6x+5)), so:

(6x+5)

We get rid of parentheses

6x+5

Back to the equation:

-(6x+5)



We add all the numbers together, and all the variables

4x-(6x+5)+45=0

We get rid of parentheses

4x-6x-5+45=0

We add all the numbers together, and all the variables

-2x+40=0

We move all terms containing x to the left, all other terms to the right

-2x=-40

x=-40/-2

x=+20

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