3x+(x+10)+5x+(2x+2)=56

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Solution for 3x+(x+10)+5x+(2x+2)=56 equation: 



3x+(x+10)+5x+(2x+2)=56

We move all terms to the left:

3x+(x+10)+5x+(2x+2)-(56)=0

We add all the numbers together, and all the variables

8x+(x+10)+(2x+2)-56=0

We get rid of parentheses

8x+x+2x+10+2-56=0

We add all the numbers together, and all the variables

11x-44=0

We move all terms containing x to the left, all other terms to the right

11x=44

x=44/11

x=4

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