(3x)+(x+20)+32=180

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Solution for (3x)+(x+20)+32=180 equation: 



(3x)+(x+20)+32=180

We move all terms to the left:

(3x)+(x+20)+32-(180)=0

We add all the numbers together, and all the variables

3x+(x+20)-148=0

We get rid of parentheses

3x+x+20-148=0

We add all the numbers together, and all the variables

4x-128=0

We move all terms containing x to the left, all other terms to the right

4x=128

x=128/4

x=32

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