4(3x-5)=-2x-48

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Solution for 4(3x-5)=-2x-48 equation: 



4(3x-5)=-2x-48

We move all terms to the left:

4(3x-5)-(-2x-48)=0

We multiply parentheses

12x-(-2x-48)-20=0

We get rid of parentheses

12x+2x+48-20=0

We add all the numbers together, and all the variables

14x+28=0

We move all terms containing x to the left, all other terms to the right

14x=-28

x=-28/14

x=-2

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