(3x)+(7x+65)+35=100

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Solution for (3x)+(7x+65)+35=100 equation: 



(3x)+(7x+65)+35=100

We move all terms to the left:

(3x)+(7x+65)+35-(100)=0

We add all the numbers together, and all the variables

3x+(7x+65)-65=0

We get rid of parentheses

3x+7x+65-65=0

We add all the numbers together, and all the variables

10x=0

x=0/10

x=0

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