6=(3/2)2+b

Solution for 6=(3/2)2+b equation:

6=(3/2)2+b

We move all terms to the left:

6-((3/2)2+b)=0


Domain of the equation: 2)2+b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

-((+3/2)2+b)+6=0

We multiply all the terms by the denominator


-((+3+6*2)2+b)=0


We calculate terms in parentheses: -((+3+6*2)2+b), so:

(+3+6*2)2+b

determiningTheFunctionDomain
b+(+3+6*2)2

We add all the numbers together, and all the variables

b+152

Back to the equation:

-(b+152)


We get rid of parentheses

-b-152=0

We add all the numbers together, and all the variables

-1b-152=0

We move all terms containing b to the left, all other terms to the right

-b=152

b=152/-1

b=-152