(3w-8)(2-w)=0

Solution for (3w-8)(2-w)=0 equation:

(3w-8)(2-w)=0

We add all the numbers together, and all the variables

(3w-8)(-1w+2)=0

We multiply parentheses ..

(-3w^2+6w+8w-16)=0

We get rid of parentheses

-3w^2+6w+8w-16=0

We add all the numbers together, and all the variables

-3w^2+14w-16=0

a = -3; b = 14; c = -16;
Δ = b2-4ac
Δ = 142-4·(-3)·(-16)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2}{2*-3}=\frac{-16}{-6}
=2+2/3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2}{2*-3}=\frac{-12}{-6}
=+2
$