G(y-4)-7y=5(3y-2)

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Solution for G(y-4)-7y=5(3y-2) equation: 



(G-4)-7G=5(3G-2)

We move all terms to the left:

(G-4)-7G-(5(3G-2))=0

We add all the numbers together, and all the variables

-7G+(G-4)-(5(3G-2))=0

We get rid of parentheses

-7G+G-(5(3G-2))-4=0



We calculate terms in parentheses: -(5(3G-2)), so:

5(3G-2)

We multiply parentheses

15G-10

Back to the equation:

-(15G-10)



We add all the numbers together, and all the variables

-6G-(15G-10)-4=0

We get rid of parentheses

-6G-15G+10-4=0

We add all the numbers together, and all the variables

-21G+6=0

We move all terms containing G to the left, all other terms to the right

-21G=-6

G=-6/-21

G=2/7

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