(3w+4)(2-w)=0

Solution for (3w+4)(2-w)=0 equation:

(3w+4)(2-w)=0

We add all the numbers together, and all the variables

(3w+4)(-1w+2)=0

We multiply parentheses ..

(-3w^2+6w-4w+8)=0

We get rid of parentheses

-3w^2+6w-4w+8=0

We add all the numbers together, and all the variables

-3w^2+2w+8=0

a = -3; b = 2; c = +8;
Δ = b2-4ac
Δ = 22-4·(-3)·8
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-10}{2*-3}=\frac{-12}{-6}
=+2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+10}{2*-3}=\frac{8}{-6}
=-1+1/3
$