(3w-4)(2-w)=0

Solution for (3w-4)(2-w)=0 equation:

(3w-4)(2-w)=0

We add all the numbers together, and all the variables

(3w-4)(-1w+2)=0

We multiply parentheses ..

(-3w^2+6w+4w-8)=0

We get rid of parentheses

-3w^2+6w+4w-8=0

We add all the numbers together, and all the variables

-3w^2+10w-8=0

a = -3; b = 10; c = -8;
Δ = b2-4ac
Δ = 102-4·(-3)·(-8)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2}{2*-3}=\frac{-12}{-6}
=+2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2}{2*-3}=\frac{-8}{-6}
=1+1/3
$