(3t-4)(6t+2)=(6t-5)(3t+7)

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Solution for (3t-4)(6t+2)=(6t-5)(3t+7) equation: 



(3t-4)(6t+2)=(6t-5)(3t+7)

We move all terms to the left:

(3t-4)(6t+2)-((6t-5)(3t+7))=0

We multiply parentheses ..

(+18t^2+6t-24t-8)-((6t-5)(3t+7))=0



We calculate terms in parentheses: -((6t-5)(3t+7)), so:

(6t-5)(3t+7)

We multiply parentheses ..

(+18t^2+42t-15t-35)

We get rid of parentheses

18t^2+42t-15t-35

We add all the numbers together, and all the variables

18t^2+27t-35

Back to the equation:

-(18t^2+27t-35)



We get rid of parentheses

18t^2-18t^2+6t-24t-27t-8+35=0

We add all the numbers together, and all the variables

-45t+27=0

We move all terms containing t to the left, all other terms to the right

-45t=-27

t=-27/-45

t=3/5

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