(3r+5)/2+2=12-2r

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Solution for (3r+5)/2+2=12-2r equation:



(3r+5)/2+2=12-2r
We move all terms to the left:
(3r+5)/2+2-(12-2r)=0
We add all the numbers together, and all the variables
(3r+5)/2-(-2r+12)+2=0
We get rid of parentheses
(3r+5)/2+2r-12+2=0
We multiply all the terms by the denominator
(3r+5)+2r*2-12*2+2*2=0
We add all the numbers together, and all the variables
(3r+5)+2r*2-20=0
Wy multiply elements
(3r+5)+4r-20=0
We get rid of parentheses
3r+4r+5-20=0
We add all the numbers together, and all the variables
7r-15=0
We move all terms containing r to the left, all other terms to the right
7r=15
r=15/7
r=2+1/7

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