10y+2(2-y)=2-2(y+1)

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Solution for 10y+2(2-y)=2-2(y+1) equation: 



10y+2(2-y)=2-2(y+1)

We move all terms to the left:

10y+2(2-y)-(2-2(y+1))=0

We add all the numbers together, and all the variables

10y+2(-1y+2)-(2-2(y+1))=0

We multiply parentheses

10y-2y-(2-2(y+1))+4=0



We calculate terms in parentheses: -(2-2(y+1)), so:

2-2(y+1)

determiningTheFunctionDomain
-2(y+1)+2

We multiply parentheses

-2y-2+2

We add all the numbers together, and all the variables

-2y

Back to the equation:

-(-2y)



We add all the numbers together, and all the variables

8y-(-2y)+4=0

We get rid of parentheses

8y+2y+4=0

We add all the numbers together, and all the variables

10y+4=0

We move all terms containing y to the left, all other terms to the right

10y=-4

y=-4/10

y=-2/5

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