(3q+10)=6(2q-9)

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Solution for (3q+10)=6(2q-9) equation: 



(3q+10)=6(2q-9)

We move all terms to the left:

(3q+10)-(6(2q-9))=0

We get rid of parentheses

3q-(6(2q-9))+10=0



We calculate terms in parentheses: -(6(2q-9)), so:

6(2q-9)

We multiply parentheses

12q-54

Back to the equation:

-(12q-54)



We get rid of parentheses

3q-12q+54+10=0

We add all the numbers together, and all the variables

-9q+64=0

We move all terms containing q to the left, all other terms to the right

-9q=-64

q=-64/-9

q=7+1/9

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