(3p-8)(p+6)=0

Solution for (3p-8)(p+6)=0 equation:

(3p-8)(p+6)=0

We multiply parentheses ..

(+3p^2+18p-8p-48)=0

We get rid of parentheses

3p^2+18p-8p-48=0

We add all the numbers together, and all the variables

3p^2+10p-48=0

a = 3; b = 10; c = -48;
Δ = b2-4ac
Δ = 102-4·3·(-48)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-26}{2*3}=\frac{-36}{6}
=-6
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+26}{2*3}=\frac{16}{6}
=2+2/3
$