(3n-5)=(2n+15)

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Solution for (3n-5)=(2n+15) equation:



(3n-5)=(2n+15)
We move all terms to the left:
(3n-5)-((2n+15))=0
We get rid of parentheses
3n-((2n+15))-5=0
We calculate terms in parentheses: -((2n+15)), so:
(2n+15)
We get rid of parentheses
2n+15
Back to the equation:
-(2n+15)
We get rid of parentheses
3n-2n-15-5=0
We add all the numbers together, and all the variables
n-20=0
We move all terms containing n to the left, all other terms to the right
n=20

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