(3n-12)=(n+n+2)

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Solution for (3n-12)=(n+n+2) equation: 



(3n-12)=(n+n+2)

We move all terms to the left:

(3n-12)-((n+n+2))=0

We add all the numbers together, and all the variables

(3n-12)-((2n+2))=0

We get rid of parentheses

3n-((2n+2))-12=0



We calculate terms in parentheses: -((2n+2)), so:

(2n+2)

We get rid of parentheses

2n+2

Back to the equation:

-(2n+2)



We get rid of parentheses

3n-2n-2-12=0

We add all the numbers together, and all the variables

n-14=0

We move all terms containing n to the left, all other terms to the right

n=14

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