(3n-1)=+(4-n)

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Solution for (3n-1)=+(4-n) equation: 



(3n-1)=+(4-n)

We move all terms to the left:

(3n-1)-(+(4-n))=0

We add all the numbers together, and all the variables

(3n-1)-(+(-1n+4))=0

We get rid of parentheses

3n-(+(-1n+4))-1=0



We calculate terms in parentheses: -(+(-1n+4)), so:

+(-1n+4)

determiningTheFunctionDomain
(-1n+4)

We get rid of parentheses

-1n+4

Back to the equation:

-(-1n+4)



We get rid of parentheses

3n+1n-4-1=0

We add all the numbers together, and all the variables

4n-5=0

We move all terms containing n to the left, all other terms to the right

4n=5

n=5/4

n=1+1/4

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