(3n+1)(3n+1)-(3n-1)(3n-1)=4(3n)

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Solution for (3n+1)(3n+1)-(3n-1)(3n-1)=4(3n) equation:



(3n+1)(3n+1)-(3n-1)(3n-1)=4(3n)
We move all terms to the left:
(3n+1)(3n+1)-(3n-1)(3n-1)-(4(3n))=0
determiningTheFunctionDomain (3n+1)(3n+1)-(3n-1)(3n-1)-43n=0
We add all the numbers together, and all the variables
-43n+(3n+1)(3n+1)-(3n-1)(3n-1)=0
We multiply parentheses ..
(+9n^2+3n+3n+1)-43n-(3n-1)(3n-1)=0
We get rid of parentheses
9n^2+3n+3n-43n-(3n-1)(3n-1)+1=0
We multiply parentheses ..
9n^2-(+9n^2-3n-3n+1)+3n+3n-43n+1=0
We add all the numbers together, and all the variables
9n^2-(+9n^2-3n-3n+1)-37n+1=0
We get rid of parentheses
9n^2-9n^2+3n+3n-37n-1+1=0
We add all the numbers together, and all the variables
-31n=0
n=0/-31
n=0

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