8(t-2)=10(t+3)

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Solution for 8(t-2)=10(t+3) equation: 



8(t-2)=10(t+3)

We move all terms to the left:

8(t-2)-(10(t+3))=0

We multiply parentheses

8t-(10(t+3))-16=0



We calculate terms in parentheses: -(10(t+3)), so:

10(t+3)

We multiply parentheses

10t+30

Back to the equation:

-(10t+30)



We get rid of parentheses

8t-10t-30-16=0

We add all the numbers together, and all the variables

-2t-46=0

We move all terms containing t to the left, all other terms to the right

-2t=46

t=46/-2

t=-23

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