(3k+1)/(10)+(5)/(6k+2)

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Solution for (3k+1)/(10)+(5)/(6k+2) equation: 


D( k )

6*k+2 = 0

6*k+2 = 0

6*k+2 = 0

6*k+2 = 0 // - 2

6*k = -2 // : 6

k = -2/6

k = -1/3

k in (-oo:-1/3) U (-1/3:+oo)

(3*k+1)/10+5/(6*k+2) = 0

((3*k+1)*(6*k+2))/(10*(6*k+2))+(5*10)/(10*(6*k+2)) = 0

(3*k+1)*(6*k+2)+5*10 = 0

18*k^2+12*k+52 = 0

18*k^2+12*k+52 = 0

2*(9*k^2+6*k+26) = 0

9*k^2+6*k+26 = 0

DELTA = 6^2-(4*9*26)

DELTA = -900

DELTA < 0

2 = 0

2/(10*(6*k+2)) = 0

2/(10*(6*k+2)) = 0 // * 10*(6*k+2)

2 = 0

k belongs to the empty set

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