(3h+4)(8h-4)=

Solution for (3h+4)(8h-4)= equation:

(3h+4)(8h-4)=

We move all terms to the left:

(3h+4)(8h-4)-()=0

We add all the numbers together, and all the variables

(3h+4)(8h-4)=0

We multiply parentheses ..

(+24h^2-12h+32h-16)=0

We get rid of parentheses

24h^2-12h+32h-16=0

We add all the numbers together, and all the variables

24h^2+20h-16=0

a = 24; b = 20; c = -16;
Δ = b2-4ac
Δ = 202-4·24·(-16)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-44}{2*24}=\frac{-64}{48}
=-1+1/3
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+44}{2*24}=\frac{24}{48}
=1/2
$