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2x(2x-1)=180
We move all terms to the left:
2x(2x-1)-(180)=0
We multiply parentheses
4x^2-2x-180=0
a = 4; b = -2; c = -180;
Δ = b2-4ac
Δ = -22-4·4·(-180)
Δ = 2884
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2884}=\sqrt{4*721}=\sqrt{4}*\sqrt{721}=2\sqrt{721}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{721}}{2*4}=\frac{2-2\sqrt{721}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{721}}{2*4}=\frac{2+2\sqrt{721}}{8} $
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