(3b-4)18=(b-1)6

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Solution for (3b-4)18=(b-1)6 equation: 



(3b-4)18=(b-1)6

We move all terms to the left:

(3b-4)18-((b-1)6)=0

We multiply parentheses

54b-((b-1)6)-72=0



We calculate terms in parentheses: -((b-1)6), so:

(b-1)6

We multiply parentheses

6b-6

Back to the equation:

-(6b-6)



We get rid of parentheses

54b-6b+6-72=0

We add all the numbers together, and all the variables

48b-66=0

We move all terms containing b to the left, all other terms to the right

48b=66

b=66/48

b=1+3/8

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