(x-3)/5=(x-10)/6

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Solution for (x-3)/5=(x-10)/6 equation: 



(x-3)/5=(x-10)/6

We move all terms to the left:

(x-3)/5-((x-10)/6)=0

We calculate fractions


x/()+(-((x-10)*5)/()=0



We calculate terms in parentheses: +(-((x-10)*5)/(), so:

-((x-10)*5)/(

We multiply all the terms by the denominator


-((x-10)*5)



We calculate terms in parentheses: -((x-10)*5), so:

(x-10)*5

We multiply parentheses

5x-50

Back to the equation:

-(5x-50)



We get rid of parentheses

-5x+50

Back to the equation:

+(-5x+50)



We get rid of parentheses

x/()-5x+50=0

We multiply all the terms by the denominator


x-5x*()+50*()=0

We add all the numbers together, and all the variables

x-5x*()=0

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