(3b+1)=(2b+4)

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Solution for (3b+1)=(2b+4) equation: 



(3b+1)=(2b+4)

We move all terms to the left:

(3b+1)-((2b+4))=0

We get rid of parentheses

3b-((2b+4))+1=0



We calculate terms in parentheses: -((2b+4)), so:

(2b+4)

We get rid of parentheses

2b+4

Back to the equation:

-(2b+4)



We get rid of parentheses

3b-2b-4+1=0

We add all the numbers together, and all the variables

b-3=0

We move all terms containing b to the left, all other terms to the right

b=3

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