4x+5(x-3)=3(x-4)+2

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Solution for 4x+5(x-3)=3(x-4)+2 equation: 



4x+5(x-3)=3(x-4)+2

We move all terms to the left:

4x+5(x-3)-(3(x-4)+2)=0

We multiply parentheses

4x+5x-(3(x-4)+2)-15=0



We calculate terms in parentheses: -(3(x-4)+2), so:

3(x-4)+2

We multiply parentheses

3x-12+2

We add all the numbers together, and all the variables

3x-10

Back to the equation:

-(3x-10)



We add all the numbers together, and all the variables

9x-(3x-10)-15=0

We get rid of parentheses

9x-3x+10-15=0

We add all the numbers together, and all the variables

6x-5=0

We move all terms containing x to the left, all other terms to the right

6x=5

x=5/6

x=5/6

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