(3a-7)/4=(4a+5)/3

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Solution for (3a-7)/4=(4a+5)/3 equation: 



(3a-7)/4=(4a+5)/3

We move all terms to the left:

(3a-7)/4-((4a+5)/3)=0

We calculate fractions


3a/()+(-((4a+5)*4)/()=0



We calculate terms in parentheses: +(-((4a+5)*4)/(), so:

-((4a+5)*4)/(

We multiply all the terms by the denominator


-((4a+5)*4)



We calculate terms in parentheses: -((4a+5)*4), so:

(4a+5)*4

We multiply parentheses

16a+20

Back to the equation:

-(16a+20)



We get rid of parentheses

-16a-20

Back to the equation:

+(-16a-20)



We get rid of parentheses

3a/()-16a-20=0

We multiply all the terms by the denominator


3a-16a*()-20*()=0

We add all the numbers together, and all the variables

3a-16a*()=0

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