3(x+2)+2(x-3)=20

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Solution for 3(x+2)+2(x-3)=20 equation: 



3(x+2)+2(x-3)=20

We move all terms to the left:

3(x+2)+2(x-3)-(20)=0

We multiply parentheses

3x+2x+6-6-20=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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