(3a-2)(4a-4)=0

Solution for (3a-2)(4a-4)=0 equation:

(3a-2)(4a-4)=0

We multiply parentheses ..

(+12a^2-12a-8a+8)=0

We get rid of parentheses

12a^2-12a-8a+8=0

We add all the numbers together, and all the variables

12a^2-20a+8=0

a = 12; b = -20; c = +8;
Δ = b2-4ac
Δ = -202-4·12·8
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4}{2*12}=\frac{16}{24}
=2/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4}{2*12}=\frac{24}{24}
=1
$