(3a+72)=(7a-4)

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Solution for (3a+72)=(7a-4) equation: 



(3a+72)=(7a-4)

We move all terms to the left:

(3a+72)-((7a-4))=0

We get rid of parentheses

3a-((7a-4))+72=0



We calculate terms in parentheses: -((7a-4)), so:

(7a-4)

We get rid of parentheses

7a-4

Back to the equation:

-(7a-4)



We get rid of parentheses

3a-7a+4+72=0

We add all the numbers together, and all the variables

-4a+76=0

We move all terms containing a to the left, all other terms to the right

-4a=-76

a=-76/-4

a=+19

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